题目 - Odd Even Linked List
难度:中等
分析
- 使用指针记录偶数链的头结点 evenHead
- 使用奇偶指针,进行循环遍历,依次将指针的next指向下一个节点
- 连接两个链表:将奇数链表的最后一个节点 next 指向 evenHead

代码
func oddEvenList(_ head: ListNode?) -> ListNode? {
var odd = head
var even = head?.next
let evenHead = even
while even != nil && even?.next != nil {
odd?.next = odd?.next?.next
odd = odd?.next
even?.next = odd?.next
even = even?.next
}
odd?.next = evenHead
return head
}